ASTRONOMY 110
Spring 1999, Section 1
Class 9     2/1/99

Small angle formula (repeat) --- we started talking about this by imagining an object at distance d that has an angular size a. Imagine drawing a big circle through the body, with radius d. Then because a is small, the body's real diameter will be nearly the same as the arc of the big circle that passes through it, so we can say that
(diameter of body)/(2 x pi x d) = a / 360 degrees
because 2 x (pi) x d is the circumference of the big circle. This is equivalent to expressing the angle a in radians and then using the formula, that
(real diameter) = (distance) x (angular diameter in radians).
You get from degrees to radians by remembering that 360 degrees equals 2 (pi) radians. I went on to show some examples of using this small angle formaula, the first one being to define a new unit of distance, the parsec, which is defined by using the observed property of parallax.

Parsec --- A parsec is defined to be the distance to an object that has an (annual) parallax of one second of arc. In terms of the small angle formula, 1 parsec = 1 AU / 1 arc second (expressed in radians). Remember, a radian is 57.3 degrees, which is (57.3 x 60 x 60) arc seconds, or 206,265 arc seconds, so 1 arc second = 1/206,265 of a radian. Then 1 parsec = 1 AU / (1/206,265), or 206,265 AU. Since we know that 1 AU = 1.5 x 10^8 km, then 1 parsec = 3.09 x 10^13 km. It so happens that this is equal to 3.26 light years, so a parsec is not too different a length from a light year, and we tend to use either unit when talking about distances from now on. Notice that this is a coincidence: these two units are defined in completely different ways. We write parsec as pc.

Distances with parsecs --- Remember that as the distance to an object increases its parallax decreases; in other words, parallax is inversely proportional to distance. If distance is measured in parsecs, this gets particularly simple: If an object has a parallax of 1 arc second, it's distance must be 1 pc (by definition); if it has a parallax of 2 arc seconds, it is twice as close, or at 0.5 pc; if it is 2 pc away, it's parallax is 0.5 arc seconds. In other words,
distance in parsecs = 1/parallax in arc seconds .

A note on parallax --- The existence of stellar parallax is a very important link in the chain of reasoning that lets us find out distances throughout the universe, so that finding stars close enough to show annual parallax is an important enterprise. The HIPARCOS satellite recently measured many more such stars with parallaxes as small as 1 milli-arcsecond (one thousandth of an arc second). What would be the corresponding distance in parsecs?

Sizes and distances to the Moon and Sun (early measurements) --- You should treat this section mostly as illustrations of using the small angle formula to measure distances from angular sizes and real sizes of bodies. I will expect you to know that Aristarchus attempted these measurements, but I won't test you on the details of the methods. You should, however, try to follow the reasoning when it comes to solving the triangles involved.
Aristarchus (310-230 B.C.) used the timing of lunar eclipses to get a handle on the relative sizes of the Earth and Moon (see handout). The Moon travels through the Earth's shadow during a lunar eclipse in about 2.5 times the time it takes to move its own diameter. The size of the Earth's shadow at the position of the Moon is naturally related to the Earth's own diameter, being almost exactly 1 Moon diameter smaller than the Earth's diameter. So Earth's diameter is about (2.5 + 1) times the Moon's diameter, or, the Moon's diameter is 0.29 times the Earth's diameter (modern value is 0.27). Knowing the real size of the Moon and it's angular diamter (0.5 degrees) let's you work out the distance to the Moon, from the small angle formula: size = distance times 0.5 degrees in radians. He then used this distance to the Moon to try to find out the distance to the Sun (the Astronomical Unit). We saw his argument for finding the relative distances to the Sun and Moon by observing the Moon at first quarter and third quarter when the angle Earth-Moon_Sun is a right angle. He estimated the angle Moon-Earth-Sun by timing the Moon's orbit between quarters he got 87 degrees), and so could know the angle Earth-Sun_Moon he got 3 degrees). Then the small angle formula gives the Earth-Moon distance in terms of the Earth-Sun distance as
Earth-Moon = Earth-Sun times 3 degrees/57.3 degrees per radian. He got the scale about a factor of 20 too small since the Moon-Earth-Sun angle is really much closer to 90 degrees, so Earth-Sun-Moon is smaller than 3 degrees.

Hipparchus (160 - 127 B.C.) --- made many contributions, but the only one that was emphasised was the introduction of the system of Magnitudes to describe the relative brightnesses of objects in the sky. He divided the visible objects in the sky into "first magnitude", second magnitude" ... down to "sixth magnitude", which were only just visible to the naked eye. Notice that smaller numbers mean brighter. Modern masurement has shown that this is a system that is related to the ratio of brightness of two objects: second magnitude compares to first magnitude the same way sixth magnitude compares to fifth, for example. In other words, a difference in "magnitude" implies a ratio in brightness. Modern definition below.

Magnitudes (modern) --- are the astronomical way of talking about the brightness or "luminosity" (will be defined later) of objects. The magnitude scale is logarithmic so that differences of magnitude represent ratios of brightness, defined so that a difference of 5 magnitudes corresponds to a brightness ratio of 100. The scale is also upside-down: smaller magnitudes mean brighter objects.